Here I am

Ok - how does this work??????

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Paint Splaters

Union Pacific Telecommunications Tech's

Dont work for me......

Guess I'm an enigma.

(loud voice in the background says) Who you callin enigma!!?:D

Eric :rolleyes:Oo.
 
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Saw something similar on another web site.



Short answer: There are only so many possible answers. All the possible answers and the "magic" ball share the same symbol.





Mike
 
It's easy.

every time you open the page or try again it changes. when you look at it, select any # you want and the answer is the same. if you don't believe me start at the top and work your way down the answer is the same ie... 95-14= 81 96-15=81 97-16=81 do you get the picture yet ?



it messed with me for a minute











:rolleyes:



DD
 
It's easy guys

Nine is the magic number.



If you take a double digit number, say 64. 6+4 =10. Now take 10 from 64 and you come up with 54. 5+4=9. They will always equal 9. Now look at the list and the shapes for the numbers that will equal 9. 18,27,36,45,54,63,72,and 81. All the shapes are the same.



Try it.
 
yeah ok...

I get the math part, and I understand all that, but how does that thing know what number you will pick to end up with the correct symbol.

Thats some freaky crap.



Edit: I got it.
 
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Mikel had it right. Every possible answer has the exact same symbol. Cap-n-cray is also right, every possible answer is a multiple of nine. The math, with X being the 10's digit and Y being the 1's digit is: (10X + Y) - (X+Y) = 10X + Y - X - Y = 9X



Choose any number from 10-19 and the anwer is 9, choose any number from 20-29 and the answer is 18, and so on. And 9,18, 27, etc. all have the same symbol next to them (which changes to a different symbol each time you try it again). Most people who would try again would probably pick a second number that was the same as or wildly different than their first and, thus, wouldn't catch on very quickly.



Notice also that it gave an example but didn't give you the result of the math. If they had, it would have tipped off anyone who picked a number between 20 and 29 since their answer would be the same. Tricky.
 
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Along the lines of tricks, here's a riddle:



Three guys go to a hotel. They tell the man behind the desk that they want 3 rooms. He says, “10 dollars per room so that's 30 dollars. ”



So they pay and go up to their rooms. Then the deskman remembers that there is a special for 3 rooms for $25. He gives the bellhop the $5 change and tells him to take it up to them.



On the way, the bellhop realizes that he doesn't know how to split it 3 ways so he keeps 2 and gives 1 to each man.



My question is: If after the dollar refund each man paid 9 dollars and $9 x 3 men equals $27 and the bellhop only has $2, then what happened to the other dollar?
 
You are adding up the wrong numbers. You are assuming that these numbers must be added to reach 30 when in fact they should equal 25 with a subtraction. They payed nine dollars each with the refund, and they never knew that other two dollars were refunded, so you have 27 dollars paid plus a 3 dollar refund = $30. The other two bucks are insignificant, and not necessary to add to the total. The two bucks bit is just put in to throw you off the scent and detract from the logical certainty that a whole single digit 1 cannot disappear magically from a sum. That's impossible.



30-5=25 25+2(bellboy)=27 27+3(refund)=30
 
Yep, you got it. I like that riddle because with well chosen words it throws people off.



But you CAN lose a single digit 1 and here's proof using simple algebra (again a fallacy but cute):



Given A = B

A + A = B + A ... ... ... ... ... ... (Added "A" to both sides)

A + A - 2B = B + A - 2B ... (Subtracted "2B" from both sides)

2A - 2B = A - B ... ... ... ... ... . (Consolidated the terms)

2(A - B) = A - B ... ... ... ... ... (Consolidated some more)

2 = 1 ... ... ... ... ... ... ... ... ... ... (Canceled "A - B" from both sides)



Simple algebra therefore proves that 1 = 2.
 
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Originally posted by Badunit

Yep, you got it. I like that riddle because with well chosen words it throws people off.



But you CAN lose a single digit 1 and here's proof using simple algebra (again a fallacy but cute):



Given A = B

A + A = B + A ... ... ... ... ... ... (Added "A" to both sides)

A + A - 2B = B + A - 2B ... (Subtracted "2B" from both sides)

2A - 2B = A - B ... ... ... ... ... . (Consolidated the terms)

2(A - B) = A - B ... ... ... ... ... (Consolidated some more)

2 = 1 ... ... ... ... ... ... ... ... ... ... (Canceled "A - B" from both sides)



Simple algebra therefore proves that 1 = 2.



You lost me on the last two lines... . well mostly the last line.



I was taught that you can not remove numbers from a math equasion if they cancel eachother out, In that event, you are still left with a number.
 
The second to last line is the result of collecting the terms on the lefthand side of the equation:



2A - 2B can also be written as 2(A - B)



The last line is the result of dividing both sides by the term (A - B).
 
Old mechanic calculating machine

I did the same thing back in the 60's with a mechanical calculator. I divide a sum by zero. The calculator would not stop running until I unplugged it. Plugged it back in and it started dividing again. :--)



Cary:cool:
 
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