Competition ALERT: 550+HP Twinned PSD..on #2

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Competition Jesup

if you look at the name it is Turbo Diesel Registry doesnt say anything about dodge or cummins in the title. Plus we gotta keep tabs on yall :) oh yeah a few of us have goats in the field eatin grass too :--)



Travis
 
Very True! I honestly could care less what brand anyone is running, if it makes 500hp, it has MY respect! It's actually kind of cool to have other brands making big HP numbers, makes the competition on the CTD side perk their ears up and try new things!
 
Johnboy. . what rods are you run'in in the bad boy ?? surely the powder ones are not holding up to that ?? if they are thats a good tribute to them !
 
Jboys truck is an early body style so it is runnin forged rods. I dont think thier is anything special about em besides maybe some polishing and peening.





:D



Travis
 
"Uncorrected:



Max HP - 552. 2 / 897. 8 at 3550



Max Trq - 514 / 1060. 7 at 2550



Corrected:



574. 9 / 1103. 4



The Superflow dyno also has a correction factor that will tell you about what you would make on a Dynojet:



608 / 1166. 8



Max boost was 61 psi. "



Hmmmmm... .

Hey Sleddy...

I wonder why he can make it live and post a great number,but,when he is supposed to bring us all desert at one of our shows it seems to break or be broken the day before???. I am sensing a pattern here and heck he never even tried to come this year :eek: :eek: and let Dockboy steal his thunder to become the next cult hero for the Ford contigent :-laf :-laf :-laf .



Anyway,Nice job JB and congratulations... ... ... . Andy



BTW...

Sled Puller and I are still waiting for that desert you promised us. .
 
Sled Puller said:
Just got the call, on a Superflow dyno, 550+. I'll post details as I get them.



Thats getting into Sleddy range, I may start looking for more fuel..... or retire...





Ok Geno, I've tried to work this out however, it doesn't make sense, Your saying a measurement of power or alternately, velocity and acceleration

v = dp/dt So v = dp/dtSo integrating both sides gives:p = /v dtso if v is constant: p = p0 + v integrating both sides gives: p = /v dtso if v is constant: p = p0 + v is moving in a straight line, and if we measure its position along that line, then its position, velocity and acceleration can all be represented by scalar quantities in theory. I guess this makes the analysis much easier, at least in kinematics structure yielding to net force, right?
 
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