if there is a single power feed wire going up to the clearence lights, you can probably make them work without too much trouble. you'll need a 2 relay and a 2 diodes. "Y" the power cable going to them and put a diode on each leg of the "Y" and splice the one end back into the factory power wire. the other end of the "Y" [through the diode] will go to a relay that will activate when the ignition is on [you need an NO/NC 87/87a type relay]. the power wire will go through the 87a-NC input so when the truck runs, there will be no chance of power going through there to make the clearence lights come on while driving and start blinking with turn signals. feeding the power to that first relay will be a 2nd relay [NO-87] that can be getting power from a direct fused link to one of the batteries. controlling that relay will be a signal from a turn signal wire. so when you hit the keyfob unlock/lock button, the hazard lights flash, the relay [no-87] will pickup, sending power through the other relay [nc-87a] and it will flow the power through the diode to the clearence lights...
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you might need to add a resistor inline with the no relay signal. dodge's pcm pulses ±2v through all the lamp wires to make that lamp out indicator work, and that 2v moght be enough to trigger the relay, so a few watt resistor installed inline should fix that problem
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i think i have that wired right...
neat idea though...