fest3er said:With all due respect, I must disagree. Torque and force are two different things. Force is measured as pounds. Torque is the multiplication of force through distance. Work is the measure of force causing displacement. Yes, I did confuse torque and work.
Take a 2000# dragster that contains 200# of fuel. Power it with a jet engine that produces 2200# of rearward force that diminishes to 2000# of force at the end of the dragstrip matching the rate at which fuel is consumed. The dragster will have constant acceleration down the track. However, since no RPM was needed to drive the wheels, there is no HP involved. For that matter, there is no torque involved, either. There is only force involved, because only force is required to displace an object, only force is required to perform work.
Now fit the dragster with gears and a rotating shaft to turn the wheels; the gears have 1:1 ratio, and the tires have 1 foot radius. Assume the dragster weighs 2000# now. Assume that the vehicle is attached to something behind it, so that 2000# of force can be applied to the shaft before launch, and once the 2000# is reached, the tether is released. To achieve the same forward acceleration as with the jet engine, you must apply 2000# of force at the interface between the tires and the pavement. This 2000# of force can be achieved by applying 2000# 1 foot from the rotating shaft, 1000# 2 feet from the shaft, or 4000# 6" from the shaft. (We ignore any losses in the drive train for this example. ) The force applied has been multiplied through distance.
In both cases, at the end of the quarter mile, the 2000# vehicle has been displaced 1320 feet - work has been performed. In the first case, HP was not involved, because a rotating engine was not driving the wheels. In the second case, HP could be measured only after the vehicle started moving (remembering that HP=Tq*RPM/5252: at 0 RPM, HP=0).
So it is not HP that moves a vehicle. It is force. And it is possible to use mechanical advantage (torque) to multiply force.
You really seem to be confusing yourself at first, but later on you're saying it right.
First of all, in your example of the thrust powered dragster you are making a completely incorrect assumption that ZERO horsepower pushed that car down the track. I'm sorry, but that's wrong. You can apply force to an object and it not move (go push against a brick wall), but once you move it you have done work, and the rate at which you complete that work is called power. Simple enough? So, in this case, a force is generated by the engine... thrust. It moves the car down the track (does work on it), and the faster it went the more power it took (more force over less time). There are ways to derive equivalent HP from a jet's thrust... it doesn't come from a spinning shaft only.
You go on to say that it's not HP that moves a vehicle, but force. I completely agree, and that's what I said from the beginning. Torque at the wheels is the important measurement to make to determine how fast your vehicle will accelerate at a given instant in time. The same calculations can be made for braking... torque at the wheels determines max braking performance (other dymanics aside). It's important to remember, though, that races don't take place in an instant... . they take TIME!!! When you apply the time element to the measurement of rear wheel torque you get... ... ... . HORSEPOWER!! The force and velocity can be interchanged to rate of output at the rear wheels. With 300hp, for example, you can either have high rpm, low torque, and high gearing (gasser) or you can have low rpm, lower gearing, and high torque (diesel). Either way, you still have 300 HP and will still get up a hill at the same speed under steady state conditions. The diesel will just last longer, get better mileage, be more driveable, and so on. This power/RPM/HP analogy is really no more different than a teeter totter with a skinny kid on one side and a fat kid on the other. You know the skinny kid has to sit farther away to balance out (more RPM if you will... weight is torque).
John