We got alot of info from a post started by Mike Ellis entitled "over GVWR?: Slow down.
I't kinda turned into, somewhat, a physics lesson and people got a little carried away like Me. The fact of the matter is the physics of pulling heavy is relevant. I personally think that the energy a rig has on level ground at a certain weight is relevant as it will give us an idea of the time to stop the rig. We have hashed alot about Kinetic Energy and it is easy to see that a rig with lower Kinetic energy will be stopped easier than one with a higher Kinetic energy. That is the Basis of the Idea that I have that speed kills not weight.
Zari enters into the equation with Potential Energy and that is a Killer. That is why they have runaway lanes in heavy mountain terrain. I emailed JC and Mike Ellis with waht I PM'd Thomas and Zari with and it follows
I need some help here. I thought I would try to do some kind of unified eq that would take weight and speed and also the force of gravity due to grade. I dont even have a dogone scientific calculater anymore! If you had a standard right triangle of sides a,b and c a being the rise and b being the run and c the hypoteneus and you wanted the force of gravity due to grade wouldnt it be Force = weight(sin(arctan(a/b)). Try it!
I am trying to do an equation that people could use by looking at a grade sign on the road. We can get a/b easily from grade. Let me know if you see an easier way or if that is right
I need the force of a rig on a grade using weight and Grade. Dont worry about speed for now.
I think that equation will give you the force of the vehicle in Lbs but I cant check it. I cant find a calculater that can do arc tan or any other trig functions at the Moment. Once I know that Force = weight(sin(arctan(a/b)) is correct I can continue
John Ponder
I't kinda turned into, somewhat, a physics lesson and people got a little carried away like Me. The fact of the matter is the physics of pulling heavy is relevant. I personally think that the energy a rig has on level ground at a certain weight is relevant as it will give us an idea of the time to stop the rig. We have hashed alot about Kinetic Energy and it is easy to see that a rig with lower Kinetic energy will be stopped easier than one with a higher Kinetic energy. That is the Basis of the Idea that I have that speed kills not weight.
Zari enters into the equation with Potential Energy and that is a Killer. That is why they have runaway lanes in heavy mountain terrain. I emailed JC and Mike Ellis with waht I PM'd Thomas and Zari with and it follows
I need some help here. I thought I would try to do some kind of unified eq that would take weight and speed and also the force of gravity due to grade. I dont even have a dogone scientific calculater anymore! If you had a standard right triangle of sides a,b and c a being the rise and b being the run and c the hypoteneus and you wanted the force of gravity due to grade wouldnt it be Force = weight(sin(arctan(a/b)). Try it!
I am trying to do an equation that people could use by looking at a grade sign on the road. We can get a/b easily from grade. Let me know if you see an easier way or if that is right
I need the force of a rig on a grade using weight and Grade. Dont worry about speed for now.
I think that equation will give you the force of the vehicle in Lbs but I cant check it. I cant find a calculater that can do arc tan or any other trig functions at the Moment. Once I know that Force = weight(sin(arctan(a/b)) is correct I can continue
John Ponder