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Switch wiring diagram question

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I am installing an electrically actuated exhaust cutout from Race Ready Performance (4”). Since my truck does not have the power adjustable pedals I have a very nice spot currently with a blanking plate for a potential switch install location. I would like to use the dodge power adjust pedal switch but not sure if I will be able to.

Speaking with Steve at RRP he said they use a DPDT (double pole double throw) switch with a neutral ground.



I could use some input on whether the Dodge switch will work or not.



First diagram is the wiring of a common DPDT switch, just for reference.

The second is the wiring diagram between the TIPM(totally integrated power module) to the pedal adjust switch to the pedal adjust motor from the Dodge service manual.

On the Dodge switch connector shown in the wiring diagram the connector pin-out functions are labeled

Pin 1: adjustable pedals motor rearward

Pin 2: adjustable pedals output

Pin 3: blank (no wire or pin)

Pin 4: ground

Pin 5: Fused ignition switch output (run)

Pin 6: Adjustable pedals motor forward

There is that symbol below pin 5, I believe it indicates a led (light emitting diode) but not positive.



Any thoughts, I would really hate to hook up the dodge switch and burn out the cutout motor.

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Switch wiring

This is why DC is nice, if you want to reverse something just reverse the leads.



What I think to do is to feed the two centre pins one side (+) positive the other side (-) negitive. (You can bring this into the cab fed from a fused wire pair from the battery Run from each side of the top DPDT (+) and the (-) wires to each side of the motor. Then reverse the wiring from the bottom of the DPDT switch.



Keep the wire colors the same red (+) white (-). Yes it will look funny red wire from the top left terminal and white from the bottom right to the left side of the motor. From the top right of the DPDT switch (-) white to the right side of the motor and red wire from the bottom left of the DPDT switch. This changes the current flow through the motor.



I hope that I have described this properly??? (several rewrites) If I have missed something please PM me and I will be back home Friday evening and will look to see. This is a good little wiring job.
 
I got the wiring harness in and their switch and the Dodge switch are pretty much identical except for one minor thing. in the RRP wiring harness right before the switch they have a capacitor (see orange dot in wiring diagram below) and before you say anything yes I realize that the little orange circle is not the correct symbol for a capacitor.

Any ideas on why they would have it, and why you would want it going to both the LED and the motor?



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I don't think the magic orange dot is a capacitor. A capacitor would block DC and pass AC.
Are there any identifying marks on it? Could it be a form of circuit protection or just a splice?
It looks like the LED will be lit as long as the 12 VDC is present at pin 5 of the box. I would guess it is intended to be hooked to switched power and not directly to the battery.
 
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Yep... It can do that too... When a voltage potential is applied to plates of a capacitor the plates charge, one positive and one negative. Remove the potential and the capacitor retains the charge until a circuit is made between the plates, then it will discharge through the circuit - like fingers (snicker-snicker:-laf). We used to charge up a particular brick looking capacitor then place it on the bench with a BIG DO NOT TOUCH sign next to it. :confused: Judging from the yelps:eek: and choice vocabulary#@$%! that soon filled the air we figured that about 80% of the "visitors" could not read. (Visitors were friendly types like co-workers from another shift or associated shops).
Best analogy would be similar to the Light Grenade in the movie "Mom and Dad Save the World".
Oh, sorry. I got side tracked... back to the capacitor stuff...
Anyway, when the capacitor reaches its full charge current flow stops. When current flow stops the DC circuit stops working - sort of like opening a switch. A voltage potential does exist across the capacitor but no current is flowing so it will not pass a DC voltage. When AC is applied there is a difference of potential alternating between the capacitor plates - plate 1 is positive and plate 2 is negative during one phase of the AC signal and as the AC input changes plate 1 becomes more negative and plate 2 more positive. All of this change creates an AC current flow felt across the capacitor and into the circuit, or properly selected, filter the noise from an alternator, etc.
 
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