Try the calculation with a 2. 0 shock, 5/8" shafts, and . 25"id x 14" long hose. We're talking about 3 cubic inches of oil displaced into the Reservoir. The hose retains . 69 cubic inches of oil that never reaches the Remote Reservoir.
This all adds up to less than half a cup of oil that sometimes makes it's way in and out of the 2. 0 Remote Reservoir. For those of you trying to visualize this, pull out your wife's cookware. The amount of oil we're calculating is about 10 teaspoons.
I think this would support my point. Remote Reservoirs are not heat exchangers . There isn't enough oil in the reservoir of a 2. 0 shock to have any effect in cooling a shock that has 5000lbs worth of Cummins bouncing on it.
Not to beat a dead horse but... The analogy of a radiator doesn't fit. A radiators capacity is measured in Gallons vs Teaspoons. The Cummins holds 7. 3 gallons of fluid, it flows at 100% (w/the thermostat open), it is pushed by the water pump, and it's cooled by a hujungous fan, while it sits directly in 60mph wind at times. Radiators are designed to exchange heat, while Remote Reservoirs on a 2. 0 shock are not.
Even though we boarded half of the readers, I'd still like to see your calculations on a 2. 0 shock.
You don't have to apologize for disagreeing, we've talked to much over the phone calculating travel and tower heights. You gave me a schooling on flutter stacks. :-laf
I want to see these heat sinks. I've debated this too, but the cost involved with machining the aluminum sleeves wouldn't be worth it. There's no real place to get the front resi's on a Dodge into the wind to help cool them. The hot radiator air wouldn't be efficient? This is why I thought 4. 0 resi's and recirculating the oil would be a better/cost effective alternative?